extra-bonus subtitles commit
This commit is contained in:
5
subs/02jk2f2qWCc.srt.sjson
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subs/02jk2f2qWCc.srt.sjson
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subs/1Y0R0tI5NqE.srt.sjson
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subs/1Y0R0tI5NqE.srt.sjson
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subs/1Y96PfmPqDc.srt.sjson
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subs/1Y96PfmPqDc.srt.sjson
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"text": [
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||||
"INSTRUCTOR: Based on the previous method or the",
|
||||
"previous property that you saw for linear circuits, we are",
|
||||
"now ready to define the superposition method for",
|
||||
"circuit analysis.",
|
||||
"Note that the superposition method",
|
||||
"applies to linear circuits.",
|
||||
"And again, to refresh your memory, remember, we are in",
|
||||
"the EECS playground that we got into by adhering to the",
|
||||
"lumped matter discipline.",
|
||||
"And within that, we looked at the node method and the KVL",
|
||||
"KCL method that applies all over the EECS playground.",
|
||||
"And then what we'll now do is look at some methods that will",
|
||||
"apply to only a region of this playground where linear",
|
||||
"circuits reside.",
|
||||
"So the first of these methods is the superposition method.",
|
||||
"And again, it applies to linear circuits.",
|
||||
"So the method is very simple and inspired by the",
|
||||
"superposition property that we studied for linear circuits.",
|
||||
"So the method simply says this.",
|
||||
"You first find the responses of the circuit to each source",
|
||||
"acting alone.",
|
||||
"Think of this as a divide and conquer method where you take",
|
||||
"your entire circuit, and you find the responses of the",
|
||||
"circuit to each source acting alone.",
|
||||
"You turn off all the sources, and you find the response to",
|
||||
"each source acting alone.",
|
||||
"Then what you do is simply sum those individual responses.",
|
||||
"Note that this technique applies to",
|
||||
"independent sources only.",
|
||||
"So if I have a linear circuit, then this technique applies to",
|
||||
"independent sources only.",
|
||||
"Now we will look at what happens when you have",
|
||||
"dependent sources and so on in later lectures.",
|
||||
"OK, let's move ahead.",
|
||||
"The first step was find the response of the circuit to",
|
||||
"each source acting alone.",
|
||||
"But what does it mean for each source to act alone?",
|
||||
"What it means is that you turn off all the other sources.",
|
||||
"So for example, suppose we are focused on a",
|
||||
"voltage source here.",
|
||||
"What does it mean to turn off this voltage source?",
|
||||
"In other words, if I want to set this voltage to 0, what",
|
||||
"does it mean in terms of my circuit?",
|
||||
"So in terms of my circuit, what this means is that I am",
|
||||
"going to short the source.",
|
||||
"So what you do is you short the source, and you end up",
|
||||
"with a short circuit here.",
|
||||
"And that is my voltage source having been set to 0.",
|
||||
"And so I take all my voltage sources in the circuit and",
|
||||
"simply short them out.",
|
||||
"And this would be making each of the sources to act alone.",
|
||||
"OK, next let's look at a current source and see what it",
|
||||
"means to set a current source to 0.",
|
||||
"So in this case, what you do is much as you set a voltage",
|
||||
"source to 0 by shorting it out, you set the current",
|
||||
"source to 0 by open-circuiting it like so.",
|
||||
"So you create an open circuit in place of the current",
|
||||
"source, and that's what it means to set a",
|
||||
"current source to zero.",
|
||||
"OK, so now we are ready to go try out an example using the",
|
||||
"method of superposition.",
|
||||
"And again, remember the method of superposition has",
|
||||
"two parts to it.",
|
||||
"In the first part, you find the responses of the circuit",
|
||||
"to each source acting alone.",
|
||||
"And then second, you sum up the partial responses.",
|
||||
"So let's go back to our old faithful example.",
|
||||
"In this example, we have two sources, a voltage source and",
|
||||
"a current source.",
|
||||
"And let's say our goal is to find the node voltage e taken",
|
||||
"with respect to this ground.",
|
||||
"And we are going to use the superposition",
|
||||
"method to do the circuit.",
|
||||
"So I showed the circuit on the right-hand corner here.",
|
||||
"And notice that e is the node voltage that I",
|
||||
"need to figure out.",
|
||||
"So by the superposition method, I have two steps.",
|
||||
"My first step is find the responses of the circuit to",
|
||||
"each source acting alone.",
|
||||
"So what I'm going to do is let me start with finding the",
|
||||
"response of the circuit to the voltage source acting alone.",
|
||||
"So what do I do to get a subcircuit in which the",
|
||||
"voltage source is acting alone?",
|
||||
"So I want you to think about this and try to figure out",
|
||||
"what the resulting subcircuit is going to look like.",
|
||||
"I'll give you a few seconds to do that before I do it myself.",
|
||||
"All right.",
|
||||
"This is the subcircuit.",
|
||||
"And what I've done here is I've had to turn the current",
|
||||
"source off.",
|
||||
"So notice that out here I create an open circuit, and",
|
||||
"that is the result of my current source",
|
||||
"being turned off.",
|
||||
"And this is my usual ground node.",
|
||||
"And let me call this node voltage with the voltage",
|
||||
"source acting alone as ev. So ev is the partial response of",
|
||||
"the circuit to the voltage source acting alone.",
|
||||
"Now how do we go about solving for ev?",
|
||||
"Notice that we have a known pattern here.",
|
||||
"We have a voltage source connected to a pair of",
|
||||
"resistors, R1 and R2.",
|
||||
"And ev is simply the voltage across R2.",
|
||||
"Now this is a known pattern.",
|
||||
"So one thing you should keep in mind is that in circuits",
|
||||
"and electronics, we use patterns a lot.",
|
||||
"Whenever we see a pattern, we can directly go and write down",
|
||||
"the what the outward response is going to look like.",
|
||||
"What I'm going to do is throughout this course, as you",
|
||||
"we more and more patterns, I am going to alert",
|
||||
"you to these patterns.",
|
||||
"So right here is a voltage divider pattern.",
|
||||
"So for the voltage divider pattern, I can write down ev",
|
||||
"as being some fraction of the source voltage v. But the",
|
||||
"divider action is simply R2 divide by R2 plus R2.",
|
||||
"So it is simply the voltage across R2, and that is given",
|
||||
"by R2 divide by R1 plus R2.",
|
||||
"And this is a known pattern that you will find very",
|
||||
"helpful as you analyze circuits very quickly.",
|
||||
"Next let's look at I acting alone.",
|
||||
"Before we do that, what do we have so far?",
|
||||
"Again, recall, this is the circuit we",
|
||||
"are trying to analyze.",
|
||||
"We are trying to get the node voltage e.",
|
||||
"And so far we have computed the partial voltage ev due to",
|
||||
"the voltage source acting alone.",
|
||||
"As the next step-- again, this is still step one of the",
|
||||
"superposition method--",
|
||||
"let's look at the partial response of the circuit due to",
|
||||
"the current acting alone.",
|
||||
"To get the response for the current acting alone, I need",
|
||||
"to build a circuit in which the voltage",
|
||||
"source is turned off.",
|
||||
"I'll let you think for a couple of seconds as to what",
|
||||
"the circuit will look like before I draw it out for you.",
|
||||
"OK, let's go ahead.",
|
||||
"So to turn off this voltage source, all I have to do is",
|
||||
"replace it with a short circuit like so.",
|
||||
"So notice that I have replaced the voltage source with a",
|
||||
"short circuit, and I've left the current source in place.",
|
||||
"I have my ground node here.",
|
||||
"And notice that my goal is to find the partial voltage eI",
|
||||
"that is a result of the current source acting alone.",
|
||||
"So notice that I have a second pattern here.",
|
||||
"And in this case, this is a current divider pattern.",
|
||||
"Actually, this is a even simpler pattern.",
|
||||
"I simply have a current that is flowing",
|
||||
"into a pair of resistors.",
|
||||
"OK, so I have a current, I, that is flowing into a pair of",
|
||||
"resistors, R1 and R2.",
|
||||
"And so I can compute the voltage across the pair of",
|
||||
"resistors very straightforwardly.",
|
||||
"So eI is simply the resistance times the current.",
|
||||
"And the resistance of a paralel pair of resistors is",
|
||||
"simply R1 R2 divide by R1 plus R2 times the current I.",
|
||||
"OK, so now I have computed both ev and eI, the two",
|
||||
"partial voltages with each of the voltages acting alone.",
|
||||
"And now I am ready for step two of the",
|
||||
"superposition method.",
|
||||
"And the step two of the superposition method simply",
|
||||
"says that you sum the two partial voltages, ev and eI.",
|
||||
"So my resulting voltage e is simply the sum of the two",
|
||||
"partial voltages ev and eI.",
|
||||
"And I have those as R2 divide by R1 plus R2 times v. And I",
|
||||
"sum that to eI.",
|
||||
"And eI is R1 R2 divide by R1 plus R2 times I. And",
|
||||
"there you have it.",
|
||||
"Not surprisingly, this expression here is identical",
|
||||
"to the expression that you obtained by using the node",
|
||||
"method in the previous lecture."
|
||||
]
|
||||
}
|
||||
5
subs/227NDapJIz0.srt.sjson
Normal file
5
subs/227NDapJIz0.srt.sjson
Normal file
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{
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subs/6nj1OCvSRI8.srt.sjson
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subs/7ssVrey04Pw.srt.sjson
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subs/7ssVrey04Pw.srt.sjson
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"text": [
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||||
"PROFESSOR: In the previous segment, we saw that circuits",
|
||||
"composed of linear elements were, themselves, linear.",
|
||||
"In this segment, we will see that linear circuits or linear",
|
||||
"systems can be analyzed with extremely powerful techniques.",
|
||||
"We will study two of these properties of circuits,",
|
||||
"homogeneity and superposition, in this segment.",
|
||||
"Let's start by studying the property of homogeneity.",
|
||||
"So what does homogeneity mean?",
|
||||
"Supposing we have a system with a bunch of inputs one",
|
||||
"output here.",
|
||||
"And let's say the inputs are x1, x2, and so on.",
|
||||
"And for these xes let's say the corresponding output is y.",
|
||||
"Let me add a little cartoon here, just to",
|
||||
"make it easy to follow.",
|
||||
"As they say, a picture is worth 1,000 words.",
|
||||
"So let's say, if you have apple as an input and you get",
|
||||
"a different kind of apple as an output, then let's look at",
|
||||
"what the property of homogeneity says.",
|
||||
"If I take the same system and if I",
|
||||
"multiply each of the inputs--",
|
||||
"x1, x2, and the old output, y-- if I multiply each of the",
|
||||
"inputs with some constant, alpha, then the property of",
|
||||
"homogeneity says that the output will also be multiplied",
|
||||
"by the same value, alpha.",
|
||||
"So this is the homogeneity property.",
|
||||
"And in terms of our picture, if you have an Apple and you",
|
||||
"took a fraction of the apple out, then your output would",
|
||||
"also have the same fraction of the apple out.",
|
||||
"So this is the homogeneity property.",
|
||||
"Next let's look at another extremely powerful technique,",
|
||||
"superposition.",
|
||||
"Now superposition is a property of linear circuits,",
|
||||
"and let's first understand what this property means.",
|
||||
"So supposing I have a system here.",
|
||||
"And what I'll do is I'll apply two sets of",
|
||||
"inputs to the system.",
|
||||
"So in the first set, let's say I apply the a set of inputs,",
|
||||
"x1a, x2a, and so on.",
|
||||
"And let's say that that gives rise to the a set of outputs.",
|
||||
"And then if I take the same system--",
|
||||
"just to make it clear, let me mark it as s.",
|
||||
"If I take the same system and I apply a b set of inputs--",
|
||||
"so x1b, x2b, and so on--",
|
||||
"and if I get a corresponding output, yb, then what can we",
|
||||
"say about the resulting system?",
|
||||
"And just to make it very clear, going back to our",
|
||||
"pictures and cartoons here, let's say the a set of inputs",
|
||||
"corresponds to apples, a for apples.",
|
||||
"And the b set of inputs goes on to blueberries.",
|
||||
"So jokingly here, if I feed a bunch of apples to the system",
|
||||
"and I get applesauce at the output, and on the other hand,",
|
||||
"if I feed a bunch of blueberries to the system and",
|
||||
"I get blueberry sauce at the output, then let's do some fun",
|
||||
"stuff here.",
|
||||
"Suppose I take the same system and I feed through the system",
|
||||
"the sum of both of these inputs.",
|
||||
"In other words, if I feed it x1a, x2a, and so on, and I add",
|
||||
"to each corresponding input the b set of inputs, so I get",
|
||||
"x1b here and x2b here-- so notice that this is here, and",
|
||||
"the b set of inputs is here.",
|
||||
"So notice that all I've done is I've added up",
|
||||
"corresponding inputs.",
|
||||
"What superposition tells me is that my outputs will be a sum",
|
||||
"of the corresponding inputs.",
|
||||
"In other words, if I had ya with the a set of inputs",
|
||||
"alone, and I had yb with the b set of inputs alone, then if I",
|
||||
"sum the corresponding inputs, the a and the b inputs, then",
|
||||
"my output will be a sum of the corresponding outputs as well.",
|
||||
"And again, jokingly, if I feed apples and blueberries to the",
|
||||
"input, then in this case, jokingly again, maybe I get",
|
||||
"mixed fruit jam.",
|
||||
"How does this yield something interesting for us?",
|
||||
"Let me do a specific example of the property of",
|
||||
"superposition and see how this will yield a very interesting",
|
||||
"technique to analyze linear circuits.",
|
||||
"Again, remember, both the homogeneity and superposition",
|
||||
"property applies to linear circuits.",
|
||||
"So let me take a specific instance of",
|
||||
"superposition here.",
|
||||
"And so I take some system, a linear system, and let's say I",
|
||||
"have two inputs that I apply, v1 and v2.",
|
||||
"And let's say my goal is to find out what the output is.",
|
||||
"What I want to show you is that, by the method of",
|
||||
"superposition, I can use a divide and conquer technique.",
|
||||
"What I can do is I can take the same system and I can set",
|
||||
"the v2 output to 0 and apply just the v1.",
|
||||
"And I measure the corresponding output, y1.",
|
||||
"So y1 here is the partial output, given that I have",
|
||||
"applied a v1 alone.",
|
||||
"Similarly, I take the same system and in this case,",
|
||||
"second time around, I set v1 to 0, and I apply v2 alone.",
|
||||
"And then let's say I get y2 as my output",
|
||||
"with v2 acting alone.",
|
||||
"Then here is something very interesting.",
|
||||
"So by superposition from a previous example, recall that",
|
||||
"if I took one set of inputs and a second set of inputs and",
|
||||
"I summed up the corresponding values, then superposition",
|
||||
"said my output would be a sum of the individual outputs with",
|
||||
"just each of those applied alone.",
|
||||
"In other words, if I show the v1 as 0 and then if I sum to",
|
||||
"that the second set of inputs, 0 and v2 from here, so that",
|
||||
"this got applied here and the first set of inputs got",
|
||||
"applied here, then what superposition would say is",
|
||||
"that my output would be a sum of the two partial outputs.",
|
||||
"In other words, y1 would come from here and y2 would be the",
|
||||
"same as the y2 with the v2 applied alone.",
|
||||
"So this is an extremely powerful idea.",
|
||||
"So to recap, what have I done here?",
|
||||
"I have used a method of superposition to apply a set",
|
||||
"of inputs in the following way.",
|
||||
"I started by saying that I have a circuit and I want to",
|
||||
"apply v1 and v2 to it and compute the output.",
|
||||
"Now rather than trying to solve the circuit by applying",
|
||||
"both v1 and v2, what I did was I broke it up into two",
|
||||
"sub-problems. In the first sub-problem, what I did was I",
|
||||
"applied v1 alone and set v2 to 0, and then in the second",
|
||||
"sub-problem, I applied v2 alone and I set v1 to be 0.",
|
||||
"And I computed the two partial outputs, y1 and y2.",
|
||||
"The method of superposition then says that if I took the",
|
||||
"two corresponding sets of inputs and summed them up,",
|
||||
"then my output would be a sum of the two partial outputs.",
|
||||
"Notice that at the input here, if you look at these two",
|
||||
"inputs, the v1 plus 0 is simply the v1, v2 plus 0 is",
|
||||
"simply v2, which is the same as what I have here.",
|
||||
"So in other words, I was able to solve the circuit that",
|
||||
"contained v1 and v2 as inputs by applying just v1 alone and",
|
||||
"then v2 alone, and then by summing up the two",
|
||||
"corresponding outputs.",
|
||||
"This will yield an incredibly powerful method for us called",
|
||||
"the method of superposition."
|
||||
]
|
||||
}
|
||||
5
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Normal file
5
subs/CdS_Zi6hCeI.srt.sjson
Normal file
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|
||||
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|
||||
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|
||||
287
subs/Duh1RHZGMQ0.srt.sjson
Normal file
287
subs/Duh1RHZGMQ0.srt.sjson
Normal file
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||||
"text": [
|
||||
"PROFESSOR: In the previous segment, we looked at the",
|
||||
"Thevenin method, which applied to linear circuits.",
|
||||
"And in that method, I could take an arbitrary network, n,",
|
||||
"containing a whole bunch of sources and resistors where",
|
||||
"the current sources are voltage sources.",
|
||||
"And I could replace that with its Thevenin equivalent, where",
|
||||
"the Thevenin equivalent pattern was given by a voltage",
|
||||
"source VTH.",
|
||||
"in series with the resistance RTH.",
|
||||
"Now one of the things that I want you to think about in",
|
||||
"circuits is that whenever you have circuits containing",
|
||||
"voltages and properties involving voltages, you can",
|
||||
"immediately think of complimentary properties",
|
||||
"involving current sources.",
|
||||
"So much as I was able to replace an arbitrary network n",
|
||||
"with its Thevenin equivalent, you can think about replacing",
|
||||
"the arbitrary network n with some pattern involving a",
|
||||
"current source.",
|
||||
"And indeed, that method where you replace an arbitrary",
|
||||
"network with a pattern involving a current source is",
|
||||
"called the Norton method.",
|
||||
"So in the Norton method, what we do is we are able to",
|
||||
"replace an arbitrary network n with its Norton equivalent,",
|
||||
"where the Norton equivalent contains the current source IN",
|
||||
"in parallel with the resistance RTH.",
|
||||
"The current source in parallel with RTH is a Norton pattern,",
|
||||
"and you should contrast it with the corresponding",
|
||||
"Thevenin pattern.",
|
||||
"So a voltage source in series with a resistor is a Thevenin",
|
||||
"pattern, and a current source in parallel with the",
|
||||
"resistance is the Norton pattern.",
|
||||
"So in the case of the Norton pattern, which contains the",
|
||||
"current source IN and the Norton resistance RN, in the",
|
||||
"same manner that you defined the Thevenin equivalent, we",
|
||||
"can derive the Norton equivalent.",
|
||||
"So to obtain the current IN, what you do is you obtain the",
|
||||
"short circuit current seen at the port.",
|
||||
"So recall for the Thevenin method, I open-circuited the",
|
||||
"port here, and measured the voltage, and that was my VTH.",
|
||||
"So the Norton method, what I do is I short circuit this",
|
||||
"port and measure the current I. That current is IN, or the",
|
||||
"Norton current.",
|
||||
"And then I can get a Norton resistance RN--",
|
||||
"oh, I should say RN here-- the Norton resistance RN, which,",
|
||||
"incidentally, is identical to the Thevenin resistance RTH.",
|
||||
"I can get that in the same manner as I got RTH, which is",
|
||||
"I shut off all the independent voltage sources and current",
|
||||
"sources and simply take the resistance measure at the",
|
||||
"port, of course, without the short.",
|
||||
"I go ahead and measure the resistance seen at the port",
|
||||
"with all the voltages and currents turned off.",
|
||||
"OK?",
|
||||
"That would be my Norton resistance, RN.",
|
||||
"So again, we stated this pattern, a current source IN",
|
||||
"parallel to a Norton resistance RN, where this",
|
||||
"corresponds to the Thevenin equivalent, where I have VTH",
|
||||
"and RTH in series.",
|
||||
"So the Norton is the dual of the Thevenin.",
|
||||
"OK?",
|
||||
"Where the Thevenin is the voltage in series with the",
|
||||
"resistance, and its dual is the Norton equivalent, which",
|
||||
"is the current source in parallel with resistance.",
|
||||
"An immediate question that comes to mind is how are the",
|
||||
"Thevenin and Norton equivalents",
|
||||
"related to each other?",
|
||||
"After all, they are the duals of one another.",
|
||||
"And so notice the Thevenin equivalent on the left-hand",
|
||||
"side and the Norton equivalent on the right-hand side.",
|
||||
"The resistances RTH and the Norton",
|
||||
"resistance RN are equal.",
|
||||
"And then we can also relate the Norton current IN and the",
|
||||
"Thevenin voltage as follows.",
|
||||
"IN is VTH divided by RTH.",
|
||||
"And so if you take the Thevenin voltage and divide",
|
||||
"that by the Thevenin resistance, you get the Norton",
|
||||
"current, IN.",
|
||||
"So this very quickly shows you how you can go from the Norton",
|
||||
"to the Thevenin.",
|
||||
"One question I am often asked is when do I use the Thevenin",
|
||||
"method and when do I use the Norton method?",
|
||||
"Well, you know, that comes from experience.",
|
||||
"Like you look at circuits in one of our earlier examples",
|
||||
"where the external network contained a voltage source in",
|
||||
"series with a resistance, it made sense to take the rest of",
|
||||
"the network and turn that into Thevenin equivalent.",
|
||||
"However, if I have a basic circuit containing a current",
|
||||
"source and a resistance in parallel, then it might be",
|
||||
"easier to take my external network and convert that into",
|
||||
"a Norton equivalent.",
|
||||
"So, really, when you want to get things in",
|
||||
"parallel, think Norton.",
|
||||
"When you want to get things in series to simplify analysis,",
|
||||
"think Thevenin."
|
||||
]
|
||||
}
|
||||
5
subs/EWD-sNLs2Xw.srt.sjson
Normal file
5
subs/EWD-sNLs2Xw.srt.sjson
Normal file
@@ -0,0 +1,5 @@
|
||||
{
|
||||
"start": [],
|
||||
"end": [],
|
||||
"text": []
|
||||
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|
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5
subs/FGx1I9LAIGs.srt.sjson
Normal file
5
subs/FGx1I9LAIGs.srt.sjson
Normal file
@@ -0,0 +1,5 @@
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||||
{
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"start": [],
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"end": [],
|
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"text": []
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5
subs/IzULGSWdcGk.srt.sjson
Normal file
5
subs/IzULGSWdcGk.srt.sjson
Normal file
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{
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"start": [],
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"end": [],
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"text": []
|
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515
subs/KawScqSYew0.srt.sjson
Normal file
515
subs/KawScqSYew0.srt.sjson
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"text": [
|
||||
"PROFESSOR: So far in 6.002, you've seen how by making some",
|
||||
"simplifications of Maxwell's equations, we've ended up with",
|
||||
"very simple algebraic laws that can be",
|
||||
"used to analyze circuits.",
|
||||
"And in this little playground of ours,",
|
||||
"really good things happen.",
|
||||
"This is our EECS playground, where by making some",
|
||||
"simplifications, we've been able to really come up with",
|
||||
"very simple techniques for analyzing circuits.",
|
||||
"So today, as we build up our arsenal of techniques for",
|
||||
"analyzing circuits, we'll look at a further simplification.",
|
||||
"We're going to look at a part of this playground in which",
|
||||
"linear circuits reside.",
|
||||
"These kinds of circuits allow us to use some even more",
|
||||
"powerful techniques to analyze them.",
|
||||
"These new techniques that you will learn today include",
|
||||
"superposition, Thevenin and Norton.",
|
||||
"It's pretty amazing to think of these techniques as the",
|
||||
"bazookas of EECS.",
|
||||
"OK, let me start with a quick review as is my usual practice",
|
||||
"of what we've seen so far.",
|
||||
"So the circuit analysis method you've seen so far include,",
|
||||
"first of all, the KVL, KCL method.",
|
||||
"In this method, the KVL, KCL, and the element rules are used",
|
||||
"to analyze circuits.",
|
||||
"The KVL method, as you've seen before, is one where you take",
|
||||
"the various voltages in a loop in a circuit and they should",
|
||||
"all sum to zero.",
|
||||
"Similarly, the currents at any given node,",
|
||||
"must also sum to zero.",
|
||||
"That's KCL.",
|
||||
"And so you apply these KVL, KCL and element rules to",
|
||||
"circuits, and then go solve them.",
|
||||
"But we did see that they ended up with a very large number of",
|
||||
"equations that were quite messy to resolve.",
|
||||
"The second technique that we looked at last week included",
|
||||
"circuit decomposition rules, where you applied some of",
|
||||
"these rules to compose resistors and other elements,",
|
||||
"and solved circuits that way.",
|
||||
"And then, we looked at the node method, where you chose a",
|
||||
"ground in a circuit.",
|
||||
"And then you applied KCL at each of the nodes, the",
|
||||
"reference to the ground node.",
|
||||
"And what was interesting is that the KVL was implicit in",
|
||||
"the pattern that you used in the node method, where the",
|
||||
"pattern was the ei minus ej, divided by the resistance of a",
|
||||
"given [UNINTELLIGIBLE].",
|
||||
"And this was a pattern that you really borrowed from KVL,",
|
||||
"and this was implicitly used in the node method.",
|
||||
"The node method, of course, is the workhorse of 6.002 and can",
|
||||
"be applied to all kinds of circuits.",
|
||||
"It really applies in the entire playground of ours.",
|
||||
"So when in doubt, simply go ahead and",
|
||||
"apply the node method.",
|
||||
"OK, as I promised, we'll now look at the smaller region of",
|
||||
"the playground, and see if some interesting things happen",
|
||||
"in that playground.",
|
||||
"So to give you a quick review, let me start by looking at",
|
||||
"some basic properties of linear circuits.",
|
||||
"Following that, I will look at the superposition tool kit for",
|
||||
"your arsenal of techniques to analyze circuits.",
|
||||
"And then I will talk about the Thevenin method.",
|
||||
"And finally, I'll talk about the Norton method.",
|
||||
"OK, so let's get started with linear circuits and see what",
|
||||
"linearity means.",
|
||||
"So I want to do an example using the following little",
|
||||
"circuit, in which I have a voltage source",
|
||||
"and a current source.",
|
||||
"And my goal here is to find the voltage at this node e.",
|
||||
"And I'm going to pick a ground node here and find the voltage",
|
||||
"e referenced to this ground node that I've just",
|
||||
"marked out for you.",
|
||||
"So to analyze a circuit, you're supposed to write down",
|
||||
"the node equations.",
|
||||
"And write down the mode equations for the node.",
|
||||
"That's the only node for which we have an unknown.",
|
||||
"Recall that I have another node here, but because that is",
|
||||
"connected by a voltage source to ground, its voltage is",
|
||||
"simply V.",
|
||||
"OK, let's start by writing the node equations for the node",
|
||||
"with unknown voltage e.",
|
||||
"So let's start by looking at the current that goes from the",
|
||||
"node with voltage e to the left.",
|
||||
"And so I take e minus V divided by R1.",
|
||||
"That is the current headed in the direction from e to v.",
|
||||
"And then I add the current that is going down this edge.",
|
||||
"That is just simply e divided by R2.",
|
||||
"And then I take the current that is",
|
||||
"headed in this direction.",
|
||||
"And that is simply minus I. According to the KCL rule,",
|
||||
"they all sum up to 0.",
|
||||
"So the first thing you will notice as you write the node",
|
||||
"equation right away is that this equation here shows you",
|
||||
"that it is linear in the various voltages and currents",
|
||||
"e, V, and I. In other words, you don't have terms, no terms",
|
||||
"that are eV, or V squared, or VI, and so on.",
|
||||
"So this circuit here is",
|
||||
"characterized by the node equation.",
|
||||
"And notice that it is linear in the e, V, and I terms.",
|
||||
"OK, let's go ahead and look at this in some more detail.",
|
||||
"And I'm going to simplify the equation a little bit more to",
|
||||
"really get a much clearer sense of the linearity here.",
|
||||
"So I've written down the node equation.",
|
||||
"And I'm going to simplify by rearranging some of the terms",
|
||||
"in the equation.",
|
||||
"So let me collect the various coefficients.",
|
||||
"So let me write down e on this side, and look at and collect",
|
||||
"all the terms that multiply e.",
|
||||
"So I see a 1 by R1 term here.",
|
||||
"Let me write that down.",
|
||||
"I see a 1 by R2 term.",
|
||||
"And so e is my unknown.",
|
||||
"Let we collect the knowns on the right-hand side.",
|
||||
"So one of the knowns is I. So let me move it to the",
|
||||
"right-hand side and put that there.",
|
||||
"The other known is this one here, V divided by R1.",
|
||||
"I'm going to take it to the right-hand side.",
|
||||
"It becomes plus V divided by R1.",
|
||||
"So let me introduce a little bit of nomenclature here.",
|
||||
"So notice I've rearranged the terms. And I get some",
|
||||
"coefficients multiplying e, and that is a sum of the",
|
||||
"sources, V and I, where V has been scaled by",
|
||||
"1 divided by R1.",
|
||||
"So when you look at these terms, let's understand a",
|
||||
"couple of things.",
|
||||
"Let's understand a couple of things right away.",
|
||||
"So if you look at the coefficient of the unknown e,",
|
||||
"in general when you have a much larger circuit, it is not",
|
||||
"a single value, but rather it is a matrix of values.",
|
||||
"And it's just good to know these terms. It's called a",
|
||||
"conductance matrix.",
|
||||
"Similarly, it's usually given the symbol G.",
|
||||
"Similarly, the node voltages becomes a column vector of",
|
||||
"node voltages, and it's given the label e.",
|
||||
"And then, on the right-hand side, you have the linear sum",
|
||||
"of sources, and that is given the term S. And so you get the",
|
||||
"form G times e equals S, where G is a matrix usually, e is a",
|
||||
"column vector.",
|
||||
"And similarly, the sum of sources ends up being a column",
|
||||
"vector as well.",
|
||||
"So with that bit of cultural background in terms of what",
|
||||
"these things are called in general, let me",
|
||||
"simplify them further.",
|
||||
"And what I get now is--",
|
||||
"let's try to have e on the left-hand side all by itself,",
|
||||
"and divide both sides by the coefficient of e.",
|
||||
"And this guy here, if I simplify it, becomes R1 R2",
|
||||
"divided by R2 plus R1.",
|
||||
"So when I multiply out both sides by that, what I end up",
|
||||
"getting is I have a V here, and I have the I here.",
|
||||
"So what is the coefficient of V?",
|
||||
"So I multiply both sides by R1 R2.",
|
||||
"And so R1 and R1 cancel out.",
|
||||
"So I end up with R2 at the top.",
|
||||
"And I get R1 plus R2 down here.",
|
||||
"Similarly, so what do you think we get for I here?",
|
||||
"For I, I end up with R1 R2 divided by R1",
|
||||
"plus R2 down here.",
|
||||
"So notice that the linearity becomes much more obvious at",
|
||||
"this point where my unknown e is some constant coefficient",
|
||||
"times the voltage v and some constant coefficient times the",
|
||||
"current I.",
|
||||
"In other words, e is of the following form. e is some",
|
||||
"constant coefficient times my first source, some constant",
|
||||
"coefficient times V2, and so on.",
|
||||
"Plus some other coefficient times I1, some other",
|
||||
"coefficient times I2, and so on.",
|
||||
"So if you look at this form here, notice that this is",
|
||||
"linear in the sources VIs and IIs."
|
||||
]
|
||||
}
|
||||
5
subs/Q3IF4g9eH34.srt.sjson
Normal file
5
subs/Q3IF4g9eH34.srt.sjson
Normal file
@@ -0,0 +1,5 @@
|
||||
{
|
||||
"start": [],
|
||||
"end": [],
|
||||
"text": []
|
||||
}
|
||||
167
subs/T2NRdHHQlOA.srt.sjson
Normal file
167
subs/T2NRdHHQlOA.srt.sjson
Normal file
@@ -0,0 +1,167 @@
|
||||
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|
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|
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|
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"text": [
|
||||
"PROFESSOR: OK, so i1 is very quickly calculated by taking",
|
||||
"the difference of V and VTH and dividing that by the sum",
|
||||
"of the two resistances.",
|
||||
"So the current i1, flowing in this direction, is given by V",
|
||||
"minus VTH divided by R1 plus RTH.",
|
||||
"And there I have it.",
|
||||
"Notice that by converting the arbitrary network N into the",
|
||||
"Thevenin equivalent, I turn this into a really trivial",
|
||||
"problem where I could write down i1 simply by inspection.",
|
||||
"Finally, before we move off the topic of the Thevenin",
|
||||
"network and the Thevenin method, it is worthwhile",
|
||||
"staring at this pattern here comprising the voltage source",
|
||||
"in series with the resistance and the equation v equals vTH",
|
||||
"plus RTHi that governs the vi of the Thevenin pattern.",
|
||||
"So it's worthwhile looking at this graphically as well.",
|
||||
"So I'm going to show you a little graph here and plot the",
|
||||
"iv relation for this Thevenin pattern.",
|
||||
"And usually the way you draw these iv relations is you try",
|
||||
"to find out an open-circuit voltage.",
|
||||
"In other words, try to find out of the voltage when the",
|
||||
"current is 0, so open-circuit voltage when i is 0.",
|
||||
"So in this case, when i is set to 0 and there's no current,",
|
||||
"then the open-circuit voltage here is simply",
|
||||
"vTH so v equals vTH.",
|
||||
"So in other words, when the current is 0,",
|
||||
"my voltage is vTH.",
|
||||
"So I found one point on the iv relation for the Thevenin",
|
||||
"equivalent pattern.",
|
||||
"Next, let me find out the short-circuit current.",
|
||||
"And for the short circuit, v is set to 0.",
|
||||
"So in this case, I apply a short circuit here, and I'm",
|
||||
"going to measure the current.",
|
||||
"So the current in this case, i is given by minus",
|
||||
"vTH divided by RTH.",
|
||||
"Notice that because vTH is positive here, the current",
|
||||
"flows down in this direction and is given by vTH divided by",
|
||||
"RTH, and that is in a direction opposite to i.",
|
||||
"And so therefore, I get the minus sign.",
|
||||
"So my current is given by minus vTH divided by RTH.",
|
||||
"And so for 0 volts, I get some current here, and that is",
|
||||
"given by vTH divided by RTH.",
|
||||
"And so this voltage here is my open-circuit voltage, and this",
|
||||
"current here is my short-circuit current, OK?",
|
||||
"So this is my short-circuit current, and that's my",
|
||||
"open-circuit voltage, and my iv relation is drawn by simply",
|
||||
"connecting the two points.",
|
||||
"And the slope of this curve is given by 1 divided by RTH.",
|
||||
"So here again, to very quickly summarize, I've drawn the iv",
|
||||
"relation for this definite pattern, which has a vTH in",
|
||||
"series with an RTH and found two points on the iv relation.",
|
||||
"One is on the voltage axis, and one is on the current axis",
|
||||
"by measuring the open-circuit voltage and the short-circuit",
|
||||
"current, and then drawing a line through them."
|
||||
]
|
||||
}
|
||||
5
subs/TwQScW8yLek.srt.sjson
Normal file
5
subs/TwQScW8yLek.srt.sjson
Normal file
@@ -0,0 +1,5 @@
|
||||
{
|
||||
"start": [],
|
||||
"end": [],
|
||||
"text": []
|
||||
}
|
||||
5
subs/V1_MS_lrPsY.srt.sjson
Normal file
5
subs/V1_MS_lrPsY.srt.sjson
Normal file
@@ -0,0 +1,5 @@
|
||||
{
|
||||
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|
||||
"end": [],
|
||||
"text": []
|
||||
}
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||||
5
subs/YsaJ1ynRGyU.srt.sjson
Normal file
5
subs/YsaJ1ynRGyU.srt.sjson
Normal file
@@ -0,0 +1,5 @@
|
||||
{
|
||||
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|
||||
"end": [],
|
||||
"text": []
|
||||
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|
||||
5
subs/Z7m-xKsbQF8.srt.sjson
Normal file
5
subs/Z7m-xKsbQF8.srt.sjson
Normal file
@@ -0,0 +1,5 @@
|
||||
{
|
||||
"start": [],
|
||||
"end": [],
|
||||
"text": []
|
||||
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|
||||
5
subs/_wDszboJ7vM.srt.sjson
Normal file
5
subs/_wDszboJ7vM.srt.sjson
Normal file
@@ -0,0 +1,5 @@
|
||||
{
|
||||
"start": [],
|
||||
"end": [],
|
||||
"text": []
|
||||
}
|
||||
5
subs/bH1ytKNX_Fg.srt.sjson
Normal file
5
subs/bH1ytKNX_Fg.srt.sjson
Normal file
@@ -0,0 +1,5 @@
|
||||
{
|
||||
"start": [],
|
||||
"end": [],
|
||||
"text": []
|
||||
}
|
||||
5
subs/gJSD6jYc8jI.srt.sjson
Normal file
5
subs/gJSD6jYc8jI.srt.sjson
Normal file
@@ -0,0 +1,5 @@
|
||||
{
|
||||
"start": [],
|
||||
"end": [],
|
||||
"text": []
|
||||
}
|
||||
5
subs/hc1QrCH7pTc.srt.sjson
Normal file
5
subs/hc1QrCH7pTc.srt.sjson
Normal file
@@ -0,0 +1,5 @@
|
||||
{
|
||||
"start": [],
|
||||
"end": [],
|
||||
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|
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||||
5
subs/i9zDhWrNK5M.srt.sjson
Normal file
5
subs/i9zDhWrNK5M.srt.sjson
Normal file
@@ -0,0 +1,5 @@
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||||
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||||
"end": [],
|
||||
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|
||||
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|
||||
5
subs/jDyHfyAssLA.srt.sjson
Normal file
5
subs/jDyHfyAssLA.srt.sjson
Normal file
@@ -0,0 +1,5 @@
|
||||
{
|
||||
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||||
"end": [],
|
||||
"text": []
|
||||
}
|
||||
326
subs/kZj5cQ4SQrE.srt.sjson
Normal file
326
subs/kZj5cQ4SQrE.srt.sjson
Normal file
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"text": [
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"SPEAKER 1: At this point, I'd like to do a quick summary of",
|
||||
"all that we have covered in 6.002 so far.",
|
||||
"We began life in 6.002 by discretizing matter into",
|
||||
"lumped elements.",
|
||||
"And we agreed to observe the lumped matter discipline.",
|
||||
"What this did was it turned real life elements, as our",
|
||||
"little pickle on which we performed the fun experiment a",
|
||||
"little while ago.",
|
||||
"And we were able to turn that into lumped elements, such as",
|
||||
"a resistor, which we could use in circuits to obtain",
|
||||
"properties such as voltages and currents.",
|
||||
"And when we took these lumped elements and put them together",
|
||||
"into circuits, we got the lumped circuit abstraction.",
|
||||
"All right.",
|
||||
"So once we built these circuits containing these",
|
||||
"lumped elements, we then went on to develop an arsenal of",
|
||||
"tools that we could use to analyze circuits.",
|
||||
"So notice that the fun part of 6.002 doubled",
|
||||
"has really not begun.",
|
||||
"We just made some assumptions that allowed us to make the",
|
||||
"transition from physics and the complications of Maxwell's",
|
||||
"equations into some very simple territories where",
|
||||
"algebraic equations rule.",
|
||||
"And then, we sat down and developed some analysis",
|
||||
"techniques for the circuits that we built.",
|
||||
"Notice we really haven't built anything useful or",
|
||||
"done any fun stuff.",
|
||||
"We are still developing our tools for the",
|
||||
"circuits that we created.",
|
||||
"So we developed a bunch of circuit analysis methods.",
|
||||
"We started off with the KVL, KCL method.",
|
||||
"And in this method, you took a circuit.",
|
||||
"And you wrote the KVL, KCL equations and also the I-V",
|
||||
"relations for each of the elements.",
|
||||
"And then you got a whole series of linear equations.",
|
||||
"And we went and solved them.",
|
||||
"The second technique we learned was applying",
|
||||
"simplification rules, where you combine resistances in",
|
||||
"series and so on and so forth, a resistance in parallel or a",
|
||||
"voltage in series, and then used those to",
|
||||
"simplify the circuit.",
|
||||
"The third method that we developed was the node method.",
|
||||
"The node method is really the workhorse of our industry.",
|
||||
"When in doubt, use the node method.",
|
||||
"The node method applies to all circuits and, in fact, is used",
|
||||
"for linear or nonlinear circuits.",
|
||||
"And by and large, when in doubt, we just",
|
||||
"apply the node method.",
|
||||
"So if you look at these techniques here, they apply to",
|
||||
"any network.",
|
||||
"And then, we looked at another class of techniques, the",
|
||||
"superposition, Thevenin, and Norton.",
|
||||
"In the superposition method, we simplified a circuit into",
|
||||
"subcircuits by shutting off all sources save for one.",
|
||||
"And then we found the subcircuit result.",
|
||||
"And then we added up all the results.",
|
||||
"That was the superposition method.",
|
||||
"And then we learned about the Thevenin and Norton methods.",
|
||||
"The Thevenin method, it determined a Thevenin pattern",
|
||||
"circuit to replace an arbitrary network, while the",
|
||||
"Norton method replaced an arbitrary circuit with the",
|
||||
"Norton pattern.",
|
||||
"Now, don't forget that the superposition, Thevenin, and",
|
||||
"Norton methods apply only to linear circuits.",
|
||||
"So these techniques, superposition, Thevenin and",
|
||||
"Norton, are extremely powerful.",
|
||||
"And they will work with linear networks.",
|
||||
"And we will see a lot of situations where we have",
|
||||
"linear networks.",
|
||||
"And so these are very important techniques.",
|
||||
"And then, of course, for nonlinear networks, or for",
|
||||
"networks that contain nonlinear elements, we will",
|
||||
"largely use the node method, where the node method is",
|
||||
"really the workhorse of our industry.",
|
||||
"Now people often ask me, when do I use which technique?",
|
||||
"You've taught us the KVL, KCL method, the node method, the",
|
||||
"Norton method.",
|
||||
"Where do I apply these techniques?",
|
||||
"The way to think about it is just imagine if you are a",
|
||||
"carpenter, and you have a tool chest full of tools.",
|
||||
"You know, you have a chisel.",
|
||||
"You have a screwdriver.",
|
||||
"And you have my favorite tool, a chainsaw.",
|
||||
"So you have all of these tools.",
|
||||
"And if you asked a carpenter, well, where do you use which",
|
||||
"tool, what do you expect the carpenter would respond?",
|
||||
"The carpenter would say, well, that's why you pay a carpenter",
|
||||
"the big bucks.",
|
||||
"They know what tool to use where, and they're practiced",
|
||||
"in using it.",
|
||||
"Similarly, as engineers, as you get more practice, you",
|
||||
"will begin using these tools and beginning to figure out",
|
||||
"where to use what tool.",
|
||||
"But fundamentally, the superposition, Thevenin, and",
|
||||
"Norton methods apply to linear networks.",
|
||||
"And the node method applies anywhere.",
|
||||
"So when in doubt, just use the node method.",
|
||||
"And much like a carpenter would use a chainsaw to chop",
|
||||
"down a tree, you can use your superposition method to",
|
||||
"analyze circuits that contain a number of sources, where you",
|
||||
"can break it down into very simple subcircuits.",
|
||||
"But of course, the circuit has to be linear to begin with.",
|
||||
"So really, you will develop experience in terms of where",
|
||||
"to apply which method.",
|
||||
"But again, don't forget that the node method will apply in",
|
||||
"any situation."
|
||||
]
|
||||
}
|
||||
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"text": [
|
||||
"PROFESSOR: In this segment, we will develop a second method",
|
||||
"that will work for linear circuits.",
|
||||
"This method is called the Thevenin method, and its",
|
||||
"complementary method, the Norton method.",
|
||||
"So in order to develop this method for linear circuits,",
|
||||
"suppose you have some arbitrary network, N. And",
|
||||
"let's say in this arbitrary network you have a whole bunch",
|
||||
"of resistors, you have a whole bunch of voltage sources, Vm,",
|
||||
"and a whole bunch of current sources as well.",
|
||||
"OK, so you have a bunch of voltage sources.",
|
||||
"And these are all independent voltage sources for now.",
|
||||
"V1, V2, V3, all the way through VM.",
|
||||
"You have a whole bunch of current sources, I1, I2, I3,",
|
||||
"all the way through to In.",
|
||||
"Suppose I am interested in applying some kind of",
|
||||
"excitation due to an external current source with current i.",
|
||||
"And let us say that all I care to do is to determine the",
|
||||
"voltage, V. So the setup here is I have an arbitrary",
|
||||
"network, N, with a ton of resistors and voltage sources",
|
||||
"and current sources, all independent.",
|
||||
"And I apply an external excitation, and",
|
||||
"it's a current i.",
|
||||
"And just assume that all I want to do is to determine the",
|
||||
"voltage, V. Assume that I don't care about any internal",
|
||||
"voltages, Vi, or any internal currents, Ij, and so on.",
|
||||
"Let's say I don't care about any of",
|
||||
"those internal currents.",
|
||||
"All I care about is the voltage, V.",
|
||||
"So in a situation like this where you care about some",
|
||||
"voltage or current at some point, you can use the",
|
||||
"property of linearity and the resulting superposition",
|
||||
"property to develop an extremely powerful method to",
|
||||
"get you to your answer very quickly.",
|
||||
"So in order to develop this method, let me use the",
|
||||
"superposition technique and try to figure out the voltage,",
|
||||
"V. So the voltage V will be some combination of the linear",
|
||||
"sources in this linear circuit.",
|
||||
"So let's say, for example, I want to figure out the",
|
||||
"contribution to the voltage V due to the voltage source, Vm.",
|
||||
"What I would then do is I would set i to 0, I would set",
|
||||
"all the currents, I1 through In, to 0, and I would set all",
|
||||
"the voltages, V1 through Vm minus 1, to 0 as well, and",
|
||||
"just look at the impact on V due to Vm acting alone.",
|
||||
"So the impact on V due to Vm acting alone, and notice that",
|
||||
"once all the currents have been turned off and all the",
|
||||
"other voltages have been turned off, I'm left with a",
|
||||
"big resistor network.",
|
||||
"And I'm going to get some multiplier here.",
|
||||
"Let's label that alpha m.",
|
||||
"So that will be the result of the source Vm acting alone on",
|
||||
"the output voltage, V.",
|
||||
"Similarly, I can do the same thing for all the voltages.",
|
||||
"I can do it for V1 acting alone.",
|
||||
"I can do it for V2 acting alone, and so on and so forth.",
|
||||
"For each of those voltages, V1, V2, and so on, I get a",
|
||||
"term that looks like this.",
|
||||
"I get alpha 1 V1, alpha 2 V2, and so on and so forth, all",
|
||||
"the way through alpha m Vm.",
|
||||
"And so what I get is a sum over m of all of these terms.",
|
||||
"By applying V1 acting alone and V2 acting alone and so on,",
|
||||
"I get a term, alpha 1 V1, alpha 2 V2, and so on.",
|
||||
"Next, I'll move on to the currents, and in this case,",
|
||||
"supposing I set all the currents, say, for In--",
|
||||
"I'm going to set the small i to 0, and I'm going to set all",
|
||||
"the Vm's to 0, and I'm going to set all the currents, I1",
|
||||
"through In minus 1, to 0.",
|
||||
"So in that situation, I'm going to get some factor, Bn,",
|
||||
"that applies to In.",
|
||||
"So I've got some factor Bn, beta n, that applies to In.",
|
||||
"And that is the result of In acting alone.",
|
||||
"Similarly, I can have I1 acting alone, I2 acting alone,",
|
||||
"and so on, and for each of them, I get a term, beta 1 I1",
|
||||
"plus beta 2 I2 and so on and so forth.",
|
||||
"And I sum them all up as well over all n.",
|
||||
"So with i acting alone, I'm going to set all of the other",
|
||||
"In's and Vm's to 0, and just have i acting alone.",
|
||||
"And so therefore I will get an i, and I'm going to have some",
|
||||
"multiplier.",
|
||||
"And in this case, notice that when all the Vm's and all the",
|
||||
"In's are set to 0, I'm just left with a big resistor",
|
||||
"network here.",
|
||||
"And so it will look like a big effective resistor looking",
|
||||
"into this port.",
|
||||
"And so let me write that down as some R multiplied",
|
||||
"by the current i.",
|
||||
"So notice now that the voltage V is a sum of a bunch of",
|
||||
"components that arise from the voltages acting alone, the",
|
||||
"currents acting alone, and also the external excitation",
|
||||
"acting alone.",
|
||||
"And just recall, how did I get this?",
|
||||
"How did I get each of these terms?",
|
||||
"So this term which sums up all the voltages I got by setting",
|
||||
"all the In's to 0 and by setting the external",
|
||||
"excitation to 0.",
|
||||
"Similarly, I got the second term here by setting all the",
|
||||
"voltage sources to 0, and also by setting the external",
|
||||
"excitation to 0.",
|
||||
"And finally, this last term, I got that by setting all the",
|
||||
"currents to 0 and all the voltages to 0.",
|
||||
"So what we're going to do now is by using this insight,",
|
||||
"we're going to build up a new technique.",
|
||||
"And to give you a preview to that technique, I'm going to",
|
||||
"show you a trick that will enable you to replace this",
|
||||
"network, N, by something very, very simple.",
|
||||
"In fact, I'm going to show you that we're going to be able to",
|
||||
"replace that entire network by some voltage source and some",
|
||||
"resistor acting in series.",
|
||||
"And this will be able to replace this entire network,",
|
||||
"N, for the purpose of computing the voltage, V. So",
|
||||
"just think of that as a preview of upcoming",
|
||||
"attractions.",
|
||||
"So moving on, let's take a look at the equation that we",
|
||||
"just developed and understand that a little bit more.",
|
||||
"So if you look at the equation here that we developed, V is",
|
||||
"some component related to Vm's, some component related",
|
||||
"to In's, and some component related to the external",
|
||||
"excitation, i.",
|
||||
"So if you look at this term here, if you look at the alpha",
|
||||
"m term here, that has no units.",
|
||||
"It has no units because I have a voltage on the left-hand",
|
||||
"side and it's multiplying a voltage.",
|
||||
"Similarly, beta and In must result in a voltage, and so",
|
||||
"therefore beta n must have resistance units.",
|
||||
"And then similarly, R that is multiplying i must have",
|
||||
"resistance units as well.",
|
||||
"So notice that if you look at the Vm-related term and the",
|
||||
"In-related term, then what you see is that together they are",
|
||||
"independent of the external excitation, and the behave",
|
||||
"like a voltage.",
|
||||
"Similarly, if you look at the right-hand term here, Ri,",
|
||||
"that's a resistance multiplied by a current, and of course,",
|
||||
"that also has resulting voltage units.",
|
||||
"So let's look at the first part here, the part comprising",
|
||||
"the Vm's and the In's.",
|
||||
"That behaves like a voltage, and it is independent of",
|
||||
"external excitation.",
|
||||
"And so what I'm going to do is I am going to call it VTH.",
|
||||
"And don't worry about why I'm calling it VTH right now, but",
|
||||
"let's assume that I call it VTH.",
|
||||
"So that's a first component that is independent of",
|
||||
"external excitation and behaves like a voltage.",
|
||||
"Now if you look at the second component, as I said earlier,",
|
||||
"the second component clearly depends on the current, i.",
|
||||
"But if you look at the multiplier R, then that is",
|
||||
"also independent of external excitation and",
|
||||
"behaves like a resistor.",
|
||||
"So let's call that RTH.",
|
||||
"So again, if you look at the term that gives you V, it will",
|
||||
"now comprise a portion that we've called VTH.",
|
||||
"And it has a second component that relates to the external",
|
||||
"excitation, i, by is multiplied by something we",
|
||||
"call RTH, where the RTH is independent of the external",
|
||||
"excitation, i.",
|
||||
"So what I've just done is I've written down the excitation as",
|
||||
"a sum of a voltage here that I decided to call VTH, and I've",
|
||||
"also said that the second part is RTH times i.",
|
||||
"And that is equal to the voltage, V. So notice V equals",
|
||||
"VTH plus RTH i.",
|
||||
"So in other words, if you look at this expression here, as",
|
||||
"far as the external world is concerned-- and again, for the",
|
||||
"purpose of computing the voltage, our network N is",
|
||||
"completely indistinguishable from another network.",
|
||||
"What does that network look like?",
|
||||
"So this whole network, N, can be replaced by the following",
|
||||
"network that I'm going to show you in a quick second.",
|
||||
"So I have a voltage, VTH, here, and I have",
|
||||
"a resistance, RTH.",
|
||||
"And this is my voltage, V. And what I've done here is,",
|
||||
"according to this equation, V equals VTH plus RTH i--",
|
||||
"I have simply expressed that in circuit form as a little",
|
||||
"pattern showing a VTH and then with an RTH in series.",
|
||||
"And this is easy to see, that when i is 0, the voltage at",
|
||||
"the output here is VTH.",
|
||||
"And then if I have a short circuit where V is 0, then the",
|
||||
"current through that short circuit will simply be given",
|
||||
"by VTH divided by RTH.",
|
||||
"And so this little pattern here can now replace my",
|
||||
"network N for the purpose of computing V.",
|
||||
"This network is called the Thevenin equivalent network.",
|
||||
"And so I can take this network, replace the arbitrary",
|
||||
"network N with this network, the Thevenin equivalent",
|
||||
"network, and then I can connect my external",
|
||||
"excitation, i, and then compute the voltage V that",
|
||||
"appears across the terminals.",
|
||||
"In other words, what I've done is, using the Thevenin method,",
|
||||
"I can take an arbitrary network N. I can figure out",
|
||||
"the VTH and RTH that relate solely to that network's",
|
||||
"properties, and then replace that network with",
|
||||
"VTH and RTH in series.",
|
||||
"And the series connection is called the",
|
||||
"Thevenin equivalent network.",
|
||||
"So you will see this is another pattern.",
|
||||
"This is called the Thevenin pattern.",
|
||||
"So in circuits and electronics courses, you will see the",
|
||||
"Thevenin pattern very often.",
|
||||
"And in this pattern, you have a voltage source in series",
|
||||
"with a resistor.",
|
||||
"And again, it's easy to see that when you have I being 0,",
|
||||
"then the Thevenin voltage, VTH, appears at the output",
|
||||
"terminal as a VTH.",
|
||||
"And similarly, if you short the terminal pair here where V",
|
||||
"is 0, then your current is going to be given by the",
|
||||
"expression, VTH divided by RTH.",
|
||||
"And since the current is going to be in the direction",
|
||||
"opposite to this current, i, there will be a negative.",
|
||||
"But essentially you can see why this expression, V equals",
|
||||
"VTH plus RTH i, directly relates to the Thevenin",
|
||||
"pattern with the voltage source in series with the",
|
||||
"resistance."
|
||||
]
|
||||
}
|
||||
5
subs/y07TZVIQIw4.srt.sjson
Normal file
5
subs/y07TZVIQIw4.srt.sjson
Normal file
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"end": [],
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569
subs/z4Bw9Vvx7es.srt.sjson
Normal file
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subs/z4Bw9Vvx7es.srt.sjson
Normal file
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||||
421360,
|
||||
424170,
|
||||
428450,
|
||||
429330,
|
||||
430150,
|
||||
432410,
|
||||
435730,
|
||||
437850,
|
||||
439420,
|
||||
441750,
|
||||
444840,
|
||||
447230,
|
||||
450530,
|
||||
454240,
|
||||
456780,
|
||||
457960,
|
||||
459030,
|
||||
463770,
|
||||
465980,
|
||||
469200,
|
||||
470760,
|
||||
473930,
|
||||
476100,
|
||||
477660,
|
||||
479000,
|
||||
480370,
|
||||
482990,
|
||||
486610,
|
||||
491680,
|
||||
495680,
|
||||
499130,
|
||||
502260,
|
||||
506170,
|
||||
509720,
|
||||
511390,
|
||||
515020
|
||||
],
|
||||
"end": [
|
||||
2540,
|
||||
3310,
|
||||
6590,
|
||||
7500,
|
||||
11040,
|
||||
16100,
|
||||
18490,
|
||||
19390,
|
||||
24450,
|
||||
28923,
|
||||
29910,
|
||||
33840,
|
||||
36510,
|
||||
38810,
|
||||
42210,
|
||||
46060,
|
||||
50180,
|
||||
52280,
|
||||
54600,
|
||||
58820,
|
||||
62380,
|
||||
64290,
|
||||
66460,
|
||||
69690,
|
||||
73330,
|
||||
77340,
|
||||
78390,
|
||||
80960,
|
||||
83950,
|
||||
86870,
|
||||
89980,
|
||||
93140,
|
||||
95340,
|
||||
96780,
|
||||
99670,
|
||||
102155,
|
||||
103640,
|
||||
105280,
|
||||
109240,
|
||||
112850,
|
||||
114820,
|
||||
118260,
|
||||
121460,
|
||||
123990,
|
||||
127220,
|
||||
131060,
|
||||
131520,
|
||||
133780,
|
||||
136430,
|
||||
136680,
|
||||
139000,
|
||||
143990,
|
||||
146730,
|
||||
149680,
|
||||
150690,
|
||||
152690,
|
||||
155430,
|
||||
158330,
|
||||
161100,
|
||||
163720,
|
||||
165940,
|
||||
169060,
|
||||
169800,
|
||||
174000,
|
||||
177060,
|
||||
177740,
|
||||
180880,
|
||||
182820,
|
||||
187110,
|
||||
190110,
|
||||
193180,
|
||||
196430,
|
||||
197710,
|
||||
200740,
|
||||
203810,
|
||||
205420,
|
||||
207050,
|
||||
210170,
|
||||
213230,
|
||||
214030,
|
||||
216230,
|
||||
219510,
|
||||
223370,
|
||||
226280,
|
||||
229130,
|
||||
232750,
|
||||
235370,
|
||||
238110,
|
||||
241220,
|
||||
243820,
|
||||
245450,
|
||||
250510,
|
||||
252410,
|
||||
257959,
|
||||
260260,
|
||||
262970,
|
||||
264640,
|
||||
265630,
|
||||
268580,
|
||||
270970,
|
||||
273300,
|
||||
275780,
|
||||
280010,
|
||||
281210,
|
||||
285620,
|
||||
289860,
|
||||
290700,
|
||||
293520,
|
||||
296660,
|
||||
299540,
|
||||
302500,
|
||||
305590,
|
||||
307940,
|
||||
310200,
|
||||
311840,
|
||||
314690,
|
||||
318000,
|
||||
322040,
|
||||
322690,
|
||||
325050,
|
||||
326950,
|
||||
329650,
|
||||
332130,
|
||||
332800,
|
||||
336400,
|
||||
340020,
|
||||
342710,
|
||||
344645,
|
||||
347780,
|
||||
350980,
|
||||
352770,
|
||||
356010,
|
||||
358925,
|
||||
364450,
|
||||
368350,
|
||||
370710,
|
||||
373860,
|
||||
377620,
|
||||
381470,
|
||||
384160,
|
||||
386530,
|
||||
389070,
|
||||
391950,
|
||||
396610,
|
||||
398890,
|
||||
402680,
|
||||
407260,
|
||||
410100,
|
||||
413710,
|
||||
417740,
|
||||
421360,
|
||||
424170,
|
||||
428450,
|
||||
429330,
|
||||
430150,
|
||||
432410,
|
||||
435730,
|
||||
437850,
|
||||
439420,
|
||||
441750,
|
||||
444840,
|
||||
447230,
|
||||
450530,
|
||||
454240,
|
||||
456780,
|
||||
457960,
|
||||
459030,
|
||||
463770,
|
||||
465980,
|
||||
469200,
|
||||
470760,
|
||||
473930,
|
||||
476100,
|
||||
477660,
|
||||
479000,
|
||||
480370,
|
||||
482990,
|
||||
486610,
|
||||
491680,
|
||||
495680,
|
||||
499130,
|
||||
502260,
|
||||
506170,
|
||||
509720,
|
||||
511390,
|
||||
515020,
|
||||
517880
|
||||
],
|
||||
"text": [
|
||||
"PROFESSOR: Let's move on from here, now that we've seen the",
|
||||
"Thevenin pattern.",
|
||||
"What I'd like to do is continue analyzing this a",
|
||||
"little bit more.",
|
||||
"As I said earlier, the Thevenin pattern replaces the",
|
||||
"arbitrary network, N. And VTH here in the Thevenin network",
|
||||
"is simply the open circuit voltage seen at",
|
||||
"the terminal pair.",
|
||||
"In other words, if I looked at network N and I simply",
|
||||
"measured the voltage at the terminal pair, it has to be an",
|
||||
"open circuit voltage.",
|
||||
"That is, without anything connected there, then whatever",
|
||||
"voltage I measure there would be the Thevenin voltage.",
|
||||
"Notice that you can see the same thing here.",
|
||||
"If I measure the voltage at that point, without any",
|
||||
"external excitation, with an open circuit here, then VTH",
|
||||
"would directly appear at the terminal, and I would be able",
|
||||
"to measure the Thevenin voltage.",
|
||||
"Similarly, what is RTH ?",
|
||||
"RTH is simply the resistance of the network seen at the",
|
||||
"terminal there, with all the voltages, Vm's, and all the",
|
||||
"currents, In's, set to 0.",
|
||||
"In other words, the way you can find the Thevenin",
|
||||
"resistance of a network is simply set all the voltages",
|
||||
"engines and all the currents to 0, and then go ahead and",
|
||||
"simply measure the resistance looking into",
|
||||
"that terminal pair.",
|
||||
"And that will give you RTH.",
|
||||
"Again, as a quick summary, given any network n, and this",
|
||||
"case a network with independent voltage and",
|
||||
"current sources, I can find a Thevenin equivalent which",
|
||||
"comprises a Thevenin voltage, VTH, and a",
|
||||
"resistance, RTH, as follows.",
|
||||
"I open-circuit the connection.",
|
||||
"In other words, I don't connect anything to the",
|
||||
"terminal pair when I'm measuring the voltage V. I",
|
||||
"measure the open circuit voltage there,",
|
||||
"and that is my VTH.",
|
||||
"Then I turn off all my current sources and voltage sources",
|
||||
"inside the network N, and simply measure its resistance.",
|
||||
"And that is RTH.",
|
||||
"So that's how I can get RTH and VTH by measurement.",
|
||||
"And for the purpose of computing some property such",
|
||||
"as the voltage when an external excitation is",
|
||||
"applied, I can use those values of VTH and RTH to",
|
||||
"replace the entire arbitrary network N with this Thevenin",
|
||||
"equivalent pattern.",
|
||||
"This is a very, very powerful technique, and we will see",
|
||||
"some examples of this shortly.",
|
||||
"OK.",
|
||||
"So we are ready to define the Thevenin method.",
|
||||
"So in the Thevenin method, you are given some network N,",
|
||||
"maybe a horrendous network with a whole bunch of voltage",
|
||||
"sources and current sources and resistors and",
|
||||
"so on and so forth.",
|
||||
"And you have some other external",
|
||||
"network, E. E for external.",
|
||||
"Then what I can do is, by the Thevenin method, I can break",
|
||||
"this down into a simpler problem as follows.",
|
||||
"What I would do as a first step is I would replace the",
|
||||
"network N with this Thevenin equivalent.",
|
||||
"And then as my second step, I would solve with the external",
|
||||
"network, E.",
|
||||
"So in other words, what I would do is I would replace",
|
||||
"the network N with its Thevenin equivalent as my",
|
||||
"first step.",
|
||||
"And then I would go ahead and solve with the external",
|
||||
"network E in my second step.",
|
||||
"And notice that I can compute RTH and VTH for the Thevenin",
|
||||
"equivalent using the discussion from a few minutes",
|
||||
"ago, where I can measure it by measuring the open circuit",
|
||||
"voltage and the effective resistance of the network with",
|
||||
"all sources turned off.",
|
||||
"Or I can also compute it by using superposition and",
|
||||
"turning off each of the voltages one by one.",
|
||||
"I can do it in either way.",
|
||||
"So this is the Thevenin method.",
|
||||
"Again, as a first step, I replace the network N with a",
|
||||
"Thevenin equivalent, and then I solve for the external",
|
||||
"network, E.",
|
||||
"Now you might wonder, when is this useful?",
|
||||
"So it turns out that in many cases where all you're",
|
||||
"interested in is some value, V for example, and you don't",
|
||||
"really care about what's going on inside this horrendous",
|
||||
"network N, then you can simplify your life",
|
||||
"tremendously by replacing that entire network with its",
|
||||
"Thevenin equivalent, and then solving the circuit for the",
|
||||
"voltage V based on that Thevenin equivalent.",
|
||||
"Again, this is a process where we divide up the problem into",
|
||||
"two simpler components, finding a Thevenin and then",
|
||||
"solving the resulting circuit.",
|
||||
"So let us now move on to an example and go to our old",
|
||||
"faithful little circuit here.",
|
||||
"And in this example, let us say that my goal here is to",
|
||||
"find out the current, I1.",
|
||||
"All I care about is to find out the current, I1.",
|
||||
"Now of course I can go ahead and apply the Norton",
|
||||
"method and do it.",
|
||||
"But let us say that in this case I want to apply the",
|
||||
"Thevenin method and use this as an example, and I'm going",
|
||||
"to show you how simple it can get.",
|
||||
"So to apply the Thevenin method, remember the first",
|
||||
"part was to identify some sub-network and replace that",
|
||||
"by its Thevenin equivalent.",
|
||||
"So what I'm going to do is I'm going to identify this network",
|
||||
"here as the arbitrary network N whose Thevenin equivalent",
|
||||
"I'm going to find.",
|
||||
"And then I'm going to view the network on the left-hand side,",
|
||||
"the voltage and resistance, as the network E. And the reason",
|
||||
"I'm going to do that is, notice that if I replace",
|
||||
"network N with a Thevenin equivalent, which would be",
|
||||
"simply a resistance and a voltage, notice that the",
|
||||
"resulting circuit would be very simple to analyze,",
|
||||
"because it would have pair of voltages and a pair of",
|
||||
"resistances in series.",
|
||||
"Let me we go ahead and find the Thevenin equivalent for",
|
||||
"network one in step one of the Thevenin method.",
|
||||
"So I'm going to replace network N by its Thevenin",
|
||||
"equivalent.",
|
||||
"So my network E is going to stay the same.",
|
||||
"So E hasn't changed.",
|
||||
"I'm trying to figure out the value of I1.",
|
||||
"And I'm going to replace the network N with this Thevenin",
|
||||
"equivalent.",
|
||||
"So the Thevenin equivalent will fit in here into this",
|
||||
"box, and let me draw the Thevenin pattern, just to be",
|
||||
"clear, where this is R Thevenin",
|
||||
"and this is V Thevenin.",
|
||||
"And we'll replace network N with its Thevenin equivalent,",
|
||||
"and in order to do that, I need to find all the values of",
|
||||
"RTH and VTH.",
|
||||
"And let me go ahead and do that next.",
|
||||
"Continuing with step one of the Thevenin method, I have my",
|
||||
"network N. And I need to find out VTH and RTH for that",
|
||||
"network N. And again, as a reminder, this is what I have",
|
||||
"for VTH and RTH.",
|
||||
"So let me first find out the VTH.",
|
||||
"And as I told you earlier, VTH is simply the open circuit",
|
||||
"voltage of the network N. So how do I find out what the",
|
||||
"open circuit voltage of that network N is?",
|
||||
"Well, it's pretty straightforward.",
|
||||
"Let me draw the network here.",
|
||||
"Let's have an R2 here, and I have a current here.",
|
||||
"And the open circuit voltage is my Thevenin voltage, VTH.",
|
||||
"So here's your simple pattern.",
|
||||
"I have a current I that is flowing into a resistance R2.",
|
||||
"And so therefore VTH is simply I times R2.",
|
||||
"So that gives me VTH.",
|
||||
"So the second step, I need to find out RTH.",
|
||||
"And the way I'm going to find out RTH is I'm going to turn",
|
||||
"off all the independent sources inside network N, and",
|
||||
"then measure the resistance looking in.",
|
||||
"So this was my network from before.",
|
||||
"This corresponds to this network.",
|
||||
"I'll do the same now.",
|
||||
"So I'm going to put my network in there.",
|
||||
"And the difference is that I'm going to turn off all the",
|
||||
"voltages and currents that are",
|
||||
"independent inside that network.",
|
||||
"So as I draw it out, R2 stays the same.",
|
||||
"But here, what I'm going to do is I'm going to turn off my",
|
||||
"current source and open-circuit that.",
|
||||
"So I'm going to turn off my current source, and so now,",
|
||||
"RTH will simply be the resistance looking in.",
|
||||
"That is easy enough to do.",
|
||||
"So RTH is simply R2.",
|
||||
"So there you have it.",
|
||||
"I've computed VTH and RTH, and that lets me develop my",
|
||||
"Thevenin network, and I'm ready for step two.",
|
||||
"So as I said earlier, VTH and RTH are given",
|
||||
"by these two values.",
|
||||
"And what I'm going to do is I'm going to replace the",
|
||||
"network N with its Thevenin equivalent.",
|
||||
"Network E stays the same.",
|
||||
"I show that here.",
|
||||
"That hasn't changed.",
|
||||
"But now what I'm going to do is I'm going to replace the",
|
||||
"network N with its Thevenin equivalent like so.",
|
||||
"But I get the RTH in series with the VTH, and the VTH is",
|
||||
"given by IR2 and RTH is given by R2.",
|
||||
"So in step two, I now need to solve with the external",
|
||||
"network E applied to the Thevenin equivalent network",
|
||||
"that as replaced the original network N. So this is, again,",
|
||||
"a very simple circuit, and recall all that I",
|
||||
"cared about was I1.",
|
||||
"And so, let me let you think for a couple of seconds about",
|
||||
"what the value of I1 is before I go and do it myself."
|
||||
]
|
||||
}
|
||||
Reference in New Issue
Block a user