The answer is 2*x^2*y + 5 -
A numerical input problem accepts a line of text input from the student, and evaluates the input for correctness based on its numerical value.
-The answer is correct if it is within a specified numerical tolerance of the expected answer.
-Enter the number of fingers on a human hand:
-Explanation
-If you look at your hand, you can count that you have five fingers.
-Test numerical problem.
-Explanation
-If you look at your hand, you can count that you have five fingers.
-Another test numerical problem.
-Explanation
-If you look at your hand, you can count that you have five fingers.
-- Optional. Help us improve our hints! Which hint was most helpful to you? -
- - - - % for answer, pk_dict in answer_to_hints.items(): - % for hint_pk, hint_text in pk_dict.items(): -- - ${hint_text} -
- % endfor - % endfor - -- Don't like any of the hints above? - - Write your own! -
-- Choose the incorrect answer for which you want to write a hint: -
- % else: -- Optional. Help other students by submitting a hint! Pick one of your previous - answers for which you would like to write a hint: -
- % endif - % for answer in user_submissions: - ${answer}- Back -
- % endif - -- Write a hint for other students who get the wrong answer of . -
-Read about what makes a good hint.
- - -- Back -
-${error}
- -% for definition_id in all_hints: -
- ${hint[0]}
-
- Votes:
-
-
${error}
- - -% if field == 'mod_queue': - -% endif - -%block> \ No newline at end of file diff --git a/lms/urls.py b/lms/urls.py index 078797bf3a..74f9eead03 100644 --- a/lms/urls.py +++ b/lms/urls.py @@ -870,13 +870,6 @@ urlpatterns += ( url(r'^debug/show_parameters$', 'debug.views.show_parameters'), ) -# Crowdsourced hinting instructor manager. -if settings.FEATURES.get('ENABLE_HINTER_INSTRUCTOR_VIEW'): - urlpatterns += ( - url(r'^courses/{}/hint_manager$'.format(settings.COURSE_ID_PATTERN), - 'instructor.hint_manager.hint_manager', name="hint_manager"), - ) - # enable automatic login if settings.FEATURES.get('AUTOMATIC_AUTH_FOR_TESTING'): urlpatterns += (