Add status app with simple view to check celery workers

common/djangoapps/service_status/test.py

@@ -0,0 +1,47 @@
+"""Test for async task service status"""
+
+from django.utils import unittest
+from django.test.client import Client
+from django.core.urlresolvers import reverse
+import json
+
+
+class CeleryConfigTest(unittest.TestCase):
+    """
+    Test that we can get a response from Celery
+    """
+
+    def setUp(self):
+        """
+        Create a django test client
+        """
+        self.client = Client()
+        self.ping_url = reverse('status.service.celery.ping')
+
+    def test_ping(self):
+        """
+        Try to ping celery.
+        """
+
+        # Access the service status page, which starts a delayed
+        # asynchronous task
+        response = self.client.get(self.ping_url)
+
+        # HTTP response should be successful
+        self.assertEqual(response.status_code, 200)
+
+        # Expect to get a JSON-serialized dict with
+        # task and time information
+        result_dict = json.loads(response.content)
+
+        # Was it successful?
+        self.assertTrue(result_dict['success'])
+
+        # We should get a "pong" message back
+        self.assertEqual(result_dict['value'], "pong")
+
+        # We don't know the other dict values exactly,
+        # but we can assert that they take the right form
+        self.assertTrue(isinstance(result_dict['task_id'], unicode))
+        self.assertTrue(isinstance(result_dict['time'], float))
+        self.assertTrue(result_dict['time'] > 0.0)